What is the domain of 1/(sqrt(x+36)) ?

The domain of 1/(sqrt(x+36)) is x>-36

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domain of 1/(sqrt(x+36))

domain

\frac{1}{x + 36}

x > - 36

Interval Notation

(- 36, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 36

Find undefined (singularity) points:

x = - 36

Combine real regions and undefined points for final function domain

x > - 36

f (x) = y + 6

f (x) = 3 x^{2} + 7 x + 2

f (x) = x^{\frac{1}{3}} (x^{2} - 63)

(\frac{2}{3})^{x - 3} - 2

f (x) = 1 - \frac{2 x + 3}{x - 1}