What is the domain of f(x)=(12)/(x^2-25) ?

The domain of f(x)=(12)/(x^2-25) is x 5

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domain of f(x)=(12)/(x^2-25)

domain

f (x) = \frac{12}{x ^{2} - 25}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = lo g_{10} (lo g_{∣ s i n (x) ∣} (x^{2} - 8 x + 23) - \frac{3}{lo g _{2} ( ∣ sin ( x ) ∣ )})

\frac{8 x + 9}{7 x - 8}

f (x) = \frac{x + 5}{( x - 7 ) ( x - 2 )}

f (x) = 5 + 4 x - x^{2}

y = 5 x - 3

What is the domain of f(x)=(12)/(x^2-25) ?
The domain of f(x)=(12)/(x^2-25) is x<-5\lor-5<x<5\lor x>5