What is the domain of f(x)=sqrt(5+4x-x^2) ?

The domain of f(x)=sqrt(5+4x-x^2) is -1<= x<= 5

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domain of f(x)=sqrt(5+4x-x^2)

domain

f (x) = 5 + 4 x - x^{2}

- 1 \leq x \leq 5

Interval Notation

[- 1, 5]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 5

The function domain

- 1 \leq x \leq 5

y = 5 x - 3

\frac{x ^{2} - 4 x + 3}{x ^{2} - 1}

f (x) = \frac{x ^{2} - 16}{x ^{2} - x - 6}

arccos (3 x^{2} - 2)

f (x) = e^{0.5 x} + 4 e^{- 0.5 x}

What is the domain of f(x)=sqrt(5+4x-x^2) ?
The domain of f(x)=sqrt(5+4x-x^2) is -1<= x<= 5