What is the domain of f(x)=(x^2-16)/(x^2-x-6) ?

The domain of f(x)=(x^2-16)/(x^2-x-6) is x 3

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domain of f(x)=(x^2-16)/(x^2-x-6)

domain

f (x) = \frac{x ^{2} - 16}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

arccos (3 x^{2} - 2)

f (x) = e^{0.5 x} + 4 e^{- 0.5 x}

\frac{x ^{2} - 8 x + 15}{x ^{2} - 7 x + 12}

f (x) = - 4 - x

f (x) = \frac{x ^{2} - 6 x + 8}{x - 4}

What is the domain of f(x)=(x^2-16)/(x^2-x-6) ?
The domain of f(x)=(x^2-16)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3