What is the domain of f(x)=sqrt(log_{1/3)(x^2+x+1)} ?

The domain of f(x)=sqrt(log_{1/3)(x^2+x+1)} is -1<= x<= 0

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domain of f(x)=sqrt(log_{1/3)(x^2+x+1)}

domain

f (x) = lo g_{\frac{1}{3}} (x^{2} + x + 1)

- 1 \leq x \leq 0

Interval Notation

[- 1, 0]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 0

The function domain

- 1 \leq x \leq 0

f (x) = arccos (x - 1) sec (x)

\frac{1}{2 x 9 + ln ( x )}

y = 2 csc (3 x - π) + 1

2 (x - 3)^{2} + 4

ln (16 - x^{2})

What is the domain of f(x)=sqrt(log_{1/3)(x^2+x+1)} ?
The domain of f(x)=sqrt(log_{1/3)(x^2+x+1)} is -1<= x<= 0