What is the domain of ln(x^2+3)+4/(sqrt(x^2+3)) ?

The domain of ln(x^2+3)+4/(sqrt(x^2+3)) is -infinity <x<infinity

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domain of ln(x^2+3)+4/(sqrt(x^2+3))

domain

ln (x^{2} + 3) + \frac{4}{x ^{2} + 3}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

Find positive values for logs:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x^{4} - 6 x^{2}

lo g_{7} (x)

f (x) = \frac{3 x}{x ^{2} - 16}

f (x) = \frac{6}{x - 1} - \frac{5}{x - 2} + 2

y = - x^{3}

What is the domain of ln(x^2+3)+4/(sqrt(x^2+3)) ?
The domain of ln(x^2+3)+4/(sqrt(x^2+3)) is -infinity <x<infinity