What is the domain of (x^2-9x)/(x^2-81) ?

The domain of (x^2-9x)/(x^2-81) is x 9

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domain of (x^2-9x)/(x^2-81)

domain

\frac{x ^{2} - 9 x}{x ^{2} - 81}

x < - 9 or - 9 < x < 9 or x > 9

Interval Notation

(- \infty, - 9) \cup (- 9, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = - 9

The function domain

x < - 9 or - 9 < x < 9 or x > 9

x^{2} + x - x

f (x) = \frac{1}{2 x ^{2}}

f (x) = \frac{1}{x - 2} + 3

f (x) = \frac{1}{x - 2} + 1

f (x) = - x^{2} + 8 x - 12

What is the domain of (x^2-9x)/(x^2-81) ?
The domain of (x^2-9x)/(x^2-81) is x<-9\lor-9<x<9\lor x>9