What is the domain of f(x)=sqrt(((x+1))/((x-1))) ?

The domain of f(x)=sqrt(((x+1))/((x-1))) is x 1

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domain of f(x)=sqrt(((x+1))/((x-1)))

domain

f (x) = \frac{( x + 1 )}{( x - 1 )}

x \leq - 1 or x > 1

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x \leq - 1 or x > 1

f (x) = \frac{4 - x ^{2}}{2 x ^{2} - 7 x - 4}

\frac{2 x + 4}{x ( x ^{2} + 3 x )}

f (x) = \frac{3 ( x ^{2} - 2 ) ^{\frac{1}{2}}}{1 - x}

sin (2 x)

f (x) = x^{2} + x^{3}

What is the domain of f(x)=sqrt(((x+1))/((x-1))) ?
The domain of f(x)=sqrt(((x+1))/((x-1))) is x<=-1\lor x>1