What is the domain of sqrt(sin(2x)) ?

The domain of sqrt(sin(2x)) is pin<= x<= pi/2+pin

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domain of sqrt(sin(2x))

domain

sin (2 x)

πn \leq x \leq \frac{π}{2} + πn

Interval Notation

[πn, \frac{π}{2} + πn]

Solution steps

Find non-negative values for radicals:

πn \leq x \leq \frac{π}{2} + πn

The function domain

πn \leq x \leq \frac{π}{2} + πn

f (x) = x^{2} + x^{3}

f (x) = \frac{ln ( x )}{x ^{2} - 5 x + 6}

\frac{x ^{2} - 4}{3 x - 1}

\frac{8 x}{7 x - 4}

f (x) = 2 x^{3} + 11 x^{2} - 8 x - 12

What is the domain of sqrt(sin(2x)) ?
The domain of sqrt(sin(2x)) is pin<= x<= pi/2+pin