What is the domain of (x^2-4)/(\sqrt[3]{x-1)} ?

The domain of (x^2-4)/(\sqrt[3]{x-1)} is x 1

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domain of (x^2-4)/(\sqrt[3]{x-1)}

domain

\frac{x ^{2} - 4}{3 x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

\frac{8 x}{7 x - 4}

f (x) = 2 x^{3} + 11 x^{2} - 8 x - 12

11 x - 9

9 - 5 x^{2}

y = lo g_{10} (x^{2} + 2 x - 3)

What is the domain of (x^2-4)/(\sqrt[3]{x-1)} ?
The domain of (x^2-4)/(\sqrt[3]{x-1)} is x<1\lor x>1