What is the domain of y=(x^2-x)/(x^2-1) ?

The domain of y=(x^2-x)/(x^2-1) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(x^2-x)/(x^2-1)

domain

y = \frac{x ^{2} - x}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = \frac{3 x + 2}{x + 4}

f (x) = lo g_{10} (5) (3 x^{2} - 5 x + 2)

f (x) = \frac{1}{( x ^{2} - x )}

f (x) = \frac{x - 1}{x + 1}

f (x) = \frac{4 x ^{2} + 6 x - 2}{4 x - 6}

What is the domain of y=(x^2-x)/(x^2-1) ?
The domain of y=(x^2-x)/(x^2-1) is x<-1\lor-1<x<1\lor x>1