What is the domain of f(x)=x-(y-1)^2=0 ?

The domain of f(x)=x-(y-1)^2=0 is -infinity <x<infinity

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domain of f(x)=x-(y-1)^2=0

domain

f (x) = x - (y - 1)^{2} = 0

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - \frac{1}{x + 4}

f (x) = \frac{1}{x ^{2} + 2 x}

f (x) = x^{2} - 2 x - ln (x + 1)

f (x) = \frac{1}{x ^{2}} + \frac{1}{x ^{3}}

f (x) = 15 x^{2} + 5 x - 1

What is the domain of f(x)=x-(y-1)^2=0 ?
The domain of f(x)=x-(y-1)^2=0 is -infinity <x<infinity