What is the domain of y=2-sqrt(9-(x+2)^2) ?

The domain of y=2-sqrt(9-(x+2)^2) is -5<= x<= 1

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domain of y=2-sqrt(9-(x+2)^2)

domain

y = 2 - 9 - (x + 2)^{2}

- 5 \leq x \leq 1

Interval Notation

[- 5, 1]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 1

The function domain

- 5 \leq x \leq 1

f (x) = \frac{x ^{2} - 10}{x ^{2} - 4}

ln (3 x - 5)

f (x) = \frac{5}{x ^{2} + x - 12}

\frac{x - 1}{x + 5}

f (x) = x^{3} + x^{2} - 2 x + 3

What is the domain of y=2-sqrt(9-(x+2)^2) ?
The domain of y=2-sqrt(9-(x+2)^2) is -5<= x<= 1