What is the domain of f(x)=(sqrt(4x-2x^2))/(x-2) ?

The domain of f(x)=(sqrt(4x-2x^2))/(x-2) is 0<= x<2

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domain of f(x)=(sqrt(4x-2x^2))/(x-2)

domain

f (x) = \frac{4 x - 2 x ^{2}}{x - 2}

0 \leq x < 2

Interval Notation

[0, 2)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

0 \leq x < 2

f (x) = lo g_{10} (\frac{x ^{2} - 9}{x - 3})

\frac{1}{3} x - 3

g (x) = \frac{x + 8}{x ^{2} - 16 + 64}

f (x) = \frac{x}{x ^{2} - x - 6}

f (x) = 120 x^{3} ln (\frac{x}{2})

What is the domain of f(x)=(sqrt(4x-2x^2))/(x-2) ?
The domain of f(x)=(sqrt(4x-2x^2))/(x-2) is 0<= x<2