What is the domain of f(x)=(sqrt(x+1))/(sqrt(2-x)) ?

The domain of f(x)=(sqrt(x+1))/(sqrt(2-x)) is -1<= x<2

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domain of f(x)=(sqrt(x+1))/(sqrt(2-x))

domain

f (x) = \frac{x + 1}{2 - x}

- 1 \leq x < 2

Interval Notation

[- 1, 2)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 1 \leq x < 2

f (y) = - (y + 4)^{2} - 391

k (x) = \frac{x + 1}{x - 1}

g (x) = \frac{2 x - 1}{x - 5}

f (x) = \frac{( x ^{2} + 2 x + 3 )}{( x - 1 )}

What is the domain of f(x)=(sqrt(x+1))/(sqrt(2-x)) ?
The domain of f(x)=(sqrt(x+1))/(sqrt(2-x)) is -1<= x<2