What is the domain of f(x)=((x^2+2x+3))/((x-1)) ?

The domain of f(x)=((x^2+2x+3))/((x-1)) is x 1

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domain of f(x)=((x^2+2x+3))/((x-1))

domain

f (x) = \frac{( x ^{2} + 2 x + 3 )}{( x - 1 )}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{4 + 5 x}{x - 1}

f (x) = \frac{( e ^{x} - 1 )}{( e ^{x} - 2 )}

\frac{ln ( x ) sinh ( x )}{x}

f (x) = lo g_{2} (1 - x^{2})

f (x) = \frac{1}{x ^{2} + x - 6} + - x + 1

What is the domain of f(x)=((x^2+2x+3))/((x-1)) ?
The domain of f(x)=((x^2+2x+3))/((x-1)) is x<1\lor x>1