What is the domain of f(x)=log_{2}(1-x^2) ?

The domain of f(x)=log_{2}(1-x^2) is -1<x<1

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domain of f(x)=log_{2}(1-x^2)

domain

f (x) = lo g_{2} (1 - x^{2})

- 1 < x < 1

Interval Notation

(- 1, 1)

Solution steps

Find positive values for logs:

- 1 < x < 1

The function domain

- 1 < x < 1

f (x) = \frac{1}{x ^{2} + x - 6} + - x + 1

f (x) = ln (x^{2} + 64)

\frac{3 x}{8 x - 1}

y = \frac{7}{x ( x - 4 )}

y = \frac{6 x - 2 - 3}{x ^{2} + 1}

What is the domain of f(x)=log_{2}(1-x^2) ?
The domain of f(x)=log_{2}(1-x^2) is -1<x<1