What is the domain of g(x)=sqrt(3x+1) ?

The domain of g(x)=sqrt(3x+1) is x>=-1/3

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domain of g(x)=sqrt(3x+1)

domain

g (x) = 3 x + 1

x \geq - \frac{1}{3}

Interval Notation

[- \frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{3}

The function domain

x \geq - \frac{1}{3}

f (x) = ln (\frac{1 - x ^{2}}{3 x ^{2} - 5 x + 2})

x^{3} - 6 x^{2} + 11 x - 6

f (x) = (0.5)^{x}

f (x) = \frac{10}{x} + \frac{x ^{2} - 4}{x - 2}

y = \frac{2 x - 7}{x - 3}

What is the domain of g(x)=sqrt(3x+1) ?
The domain of g(x)=sqrt(3x+1) is x>=-1/3