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Popular >

distance (-1,8),(4,-2)

Solution

distance

(- 1, 8), (4, - 2)

Solution

55

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 1, 8)

and

(4, - 2)

is

= (4 - (- 1))^{2} + (- 2 - 8)^{2}

Simplify

= 55

Popular Examples

domain of 2csc(1/3 (x-1))-2 domain

2 csc (\frac{1}{3} (x - 1)) - 2

asymptotes of f(x)=(3x-15)/(x^2-25)asymptotes

f (x) = \frac{3 x - 15}{x ^{2} - 25}

inverse of f(x)=x^2+5x inverse

f (x) = x^{2} + 5 x

inverse of f(x)= 1/x-1 inverse

f (x) = \frac{1}{x} - 1

domain of f(x)=5+4x-x^2 domain

f (x) = 5 + 4 x - x^{2}

Frequently Asked Questions (FAQ)

What is the distance (-1,8),(4,-2) ?
The distance (-1,8),(4,-2) is 5sqrt(5)