What is the domain of f(x)=(2x^2-4)/(3x^2+6x-45) ?

The domain of f(x)=(2x^2-4)/(3x^2+6x-45) is x 3

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domain of f(x)=(2x^2-4)/(3x^2+6x-45)

domain

f (x) = \frac{2 x ^{2} - 4}{3 x ^{2} + 6 x - 45}

x < - 5 or - 5 < x < 3 or x > 3

Interval Notation

(- \infty, - 5) \cup (- 5, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 5

The function domain

x < - 5 or - 5 < x < 3 or x > 3

f (x) = 2 + x^{3} - 2 x^{2} - x + 2

f (x) = \frac{70}{x}

f (x) = ln (0.5 + y)

4 [x + 2]

x^{2} + 64

What is the domain of f(x)=(2x^2-4)/(3x^2+6x-45) ?
The domain of f(x)=(2x^2-4)/(3x^2+6x-45) is x<-5\lor-5<x<3\lor x>3