What is the domain of 1/(2x^2+x-6) ?

The domain of 1/(2x^2+x-6) is x 3/2

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domain of 1/(2x^2+x-6)

domain

\frac{1}{2 x ^{2} + x - 6}

x < - 2 or - 2 < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - 2) \cup (- 2, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}, x = - 2

The function domain

x < - 2 or - 2 < x < \frac{3}{2} or x > \frac{3}{2}

36 x + 49

f (x) = (4 x^{3} - 48 x^{2} + 144 x)

f (x) = \frac{( x + 7 )}{x ^{2} - 49}

f (x) = \frac{17}{( 1 - 4 x ) ^{2}}

g (u) = 11 - u^{2}

What is the domain of 1/(2x^2+x-6) ?
The domain of 1/(2x^2+x-6) is x<-2\lor-2<x< 3/2 \lor x> 3/2