What is the domain of f(x)=(17)/((1-4x)^2) ?

The domain of f(x)=(17)/((1-4x)^2) is x 1/4

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domain of f(x)=(17)/((1-4x)^2)

domain

f (x) = \frac{17}{( 1 - 4 x ) ^{2}}

x < \frac{1}{4} or x > \frac{1}{4}

Interval Notation

(- \infty, \frac{1}{4}) \cup (\frac{1}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{4}

The function domain

x < \frac{1}{4} or x > \frac{1}{4}

g (u) = 11 - u^{2}

f (x) = \frac{1}{- ( x ^{2} - 6 x + 5 )}

\frac{x ^{2} + 5 x}{25 - x ^{2}}

x^{4} + 3 x^{2} + 2

\frac{2 x - 9}{2 x + 9}

What is the domain of f(x)=(17)/((1-4x)^2) ?
The domain of f(x)=(17)/((1-4x)^2) is x< 1/4 \lor x> 1/4