What is the domain of f(x)=sqrt(x+21) ?

The domain of f(x)=sqrt(x+21) is x>=-21

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domain of f(x)=sqrt(x+21)

domain

f (x) = x + 21

x \geq - 21

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 21

The function domain

x \geq - 21

(1 - x^{2})^{x}

f (x) = \frac{x - 1}{\frac{x - 1}{x - 3}}

f (x, y) = x + ln (x^{2} - 1)

y = x + 1 - 2

f (x) = 2 - x - 36 - x^{2}