What is the domain of f(x)=sqrt(1-(x-1)^2) ?

The domain of f(x)=sqrt(1-(x-1)^2) is 0<= x<= 2

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domain of f(x)=sqrt(1-(x-1)^2)

domain

f (x) = 1 - (x - 1)^{2}

0 \leq x \leq 2

Interval Notation

[0, 2]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 2

The function domain

0 \leq x \leq 2

f (x) = \frac{- 1}{x - 1}

f (x) = ln (x) - e^{x} - x

\frac{x + 1}{2 - x}

f (x) = lo g_{x} (x - 2)

f (x) = \frac{x ^{2} - 5}{2}

What is the domain of f(x)=sqrt(1-(x-1)^2) ?
The domain of f(x)=sqrt(1-(x-1)^2) is 0<= x<= 2