What is the domain of f(x)=ln(x)-e^x-x ?

The domain of f(x)=ln(x)-e^x-x is x>0

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domain of f(x)=ln(x)-e^x-x

domain

f (x) = ln (x) - e^{x} - x

x > 0

Interval Notation

(0, \infty)

Solution steps

Find positive values for logs:

x > 0

The function domain

x > 0

\frac{x + 1}{2 - x}

f (x) = lo g_{x} (x - 2)

f (x) = \frac{x ^{2} - 5}{2}

f (x) = 3 x - 1 + 2 x - 4

f (x) = 3^{2 - x} + 1