What is the domain of f(x)=ln(e^{|x^2+2x+1|}-e) ?

The domain of f(x)=ln(e^{|x^2+2x+1|}-e) is x 0

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domain of f(x)=ln(e^{|x^2+2x+1|}-e)

domain

f (x) = ln (e^{∣ x^{2} + 2 x + 1 ∣} - e)

x < - 2 or x > 0

Interval Notation

(- \infty, - 2) \cup (0, \infty)

Solution steps

Find positive values for logs:

x < - 2 or x > 0

The function domain

x < - 2 or x > 0

h (x) = \frac{x ^{2} - 4}{2}

f (x) = \frac{4 x}{x ^{2} + 1}

x^{4} - 8 x^{2} + 17

f (x) = 5 - 2 x + 2

lo g_{10} (∣ x - 1 ∣)

What is the domain of f(x)=ln(e^{|x^2+2x+1|}-e) ?
The domain of f(x)=ln(e^{|x^2+2x+1|}-e) is x<-2\lor x>0