What is the domain of (x^3-x)/(x^4+4x^3+3x^2-4x-4) ?

The domain of (x^3-x)/(x^4+4x^3+3x^2-4x-4) is x 1

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domain of (x^3-x)/(x^4+4x^3+3x^2-4x-4)

domain

\frac{x ^{3} - x}{x ^{4} + 4 x ^{3} + 3 x ^{2} - 4 x - 4}

x < - 2 or - 2 < x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 1, x = - 2

The function domain

x < - 2 or - 2 < x < - 1 or - 1 < x < 1 or x > 1

h (x) = (tan (x))

f (x) = ln (16 - x^{2})

- \frac{1}{2}

f (x) = \frac{7 x - 21}{( x - 7 ) ( x + 1 )}

f (x) = \frac{- 1}{x + 3}

What is the domain of (x^3-x)/(x^4+4x^3+3x^2-4x-4) ?
The domain of (x^3-x)/(x^4+4x^3+3x^2-4x-4) is x<-2\lor-2<x<-1\lor-1<x<1\lor x>1