What is the domain of h(x)=(tan(x)) ?

The domain of h(x)=(tan(x)) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of h(x)=(tan(x))

domain

h (x) = (tan (x))

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Interval Notation

Solution steps

Take the denominator(s) of

tan (x)

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

tan (x) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

f (x) = ln (16 - x^{2})

- \frac{1}{2}

f (x) = \frac{7 x - 21}{( x - 7 ) ( x + 1 )}

f (x) = \frac{- 1}{x + 3}

f (x) = - x^{2} - 4 x + 4

What is the domain of h(x)=(tan(x)) ?
The domain of h(x)=(tan(x)) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin