What is the domain of f(y)=\sqrt[3]{y/(y-4)} ?

The domain of f(y)=\sqrt[3]{y/(y-4)} is y 4

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domain of f(y)=\sqrt[3]{y/(y-4)}

domain

f (y) = 3 \frac{y}{y - 4}

y < 4 or y > 4

Interval Notation

(- \infty, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

y = 4

The function domain

y < 4 or y > 4

f (x) = \frac{x ( x - 1 )}{x - 1}

y = \frac{cos ( t )}{ln ∣ t + 1 ∣}

f (x) = h (x, t) = - 0.0625 t^{2} + 3 t - 20

f (x) = 3 10 x^{3} + 10

f (x, y) = arcsin (y)

What is the domain of f(y)=\sqrt[3]{y/(y-4)} ?
The domain of f(y)=\sqrt[3]{y/(y-4)} is y<4\lor y>4