What is the domain of y=(cos(t))/(ln|t+1|) ?

The domain of y=(cos(t))/(ln|t+1|) is t 0

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domain of y=(cos(t))/(ln|t+1|)

domain

y = \frac{cos ( t )}{ln ∣ t + 1 ∣}

t < - 2 or - 2 < t < - 1 or - 1 < t < 0 or t > 0

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find positive values for logs:

t < - 1 or t > - 1

Find undefined (singularity) points:

t = - 2, t = 0

Combine real regions and undefined points for final function domain

t < - 2 or - 2 < t < - 1 or - 1 < t < 0 or t > 0

f (x) = h (x, t) = - 0.0625 t^{2} + 3 t - 20

f (x) = 3 10 x^{3} + 10

f (x, y) = arcsin (y)

f (x) = 1 + \frac{1}{x} + \frac{1}{x ^{2}}

(\frac{k + 2}{k + 1})^{\frac{3}{2}}

What is the domain of y=(cos(t))/(ln|t+1|) ?
The domain of y=(cos(t))/(ln|t+1|) is t<-2\lor-2<t<-1\lor-1<t<0\lor t>0