What is the domain of f(x)=1+1/x+1/(x^2) ?

The domain of f(x)=1+1/x+1/(x^2) is x 0

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domain of f(x)=1+1/x+1/(x^2)

domain

f (x) = 1 + \frac{1}{x} + \frac{1}{x ^{2}}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

(\frac{k + 2}{k + 1})^{\frac{3}{2}}

f (x) = \frac{x + 2}{x + 3}

f (x) = (x + 3) - 2

f (x) = \frac{x}{x - 1}

\frac{x ^{3} - 8}{x ^{2} - 16}

What is the domain of f(x)=1+1/x+1/(x^2) ?
The domain of f(x)=1+1/x+1/(x^2) is x<0\lor x>0