What is the domain of f(x)= x/(sqrt(x)-1) ?

The domain of f(x)= x/(sqrt(x)-1) is 0 1

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domain of f(x)= x/(sqrt(x)-1)

domain

f (x) = \frac{x}{x - 1}

0 \leq x < 1 or x > 1

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

0 \leq x < 1 or x > 1

\frac{x ^{3} - 8}{x ^{2} - 16}

7 x - 7

6 x^{2} + 7 x + 26 x^{2} - 5 x - 6

g (s) = \frac{1}{s ^{2} - 4 - 2}

f (x) = x^{\frac{3}{4}}

What is the domain of f(x)= x/(sqrt(x)-1) ?
The domain of f(x)= x/(sqrt(x)-1) is 0<= x<1\lor x>1