What is the domain of f(x)=ln(x^3+3x^2+3x+1) ?

The domain of f(x)=ln(x^3+3x^2+3x+1) is x>-1

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domain of f(x)=ln(x^3+3x^2+3x+1)

domain

f (x) = ln (x^{3} + 3 x^{2} + 3 x + 1)

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find positive values for logs:

x > - 1

The function domain

x > - 1

y = \frac{2 x}{x ^{2} - 1}

f (x) = (1 + \frac{1}{x})^{2}

f (x) = x + \frac{256}{x ^{2}}

f (x) = - 9 - x

f (x) = \frac{2 x - 9}{2 x + 9}

What is the domain of f(x)=ln(x^3+3x^2+3x+1) ?
The domain of f(x)=ln(x^3+3x^2+3x+1) is x>-1