What is the domain of f(x)=sqrt(-x^2-3x+4) ?

The domain of f(x)=sqrt(-x^2-3x+4) is -4<= x<= 1

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domain of f(x)=sqrt(-x^2-3x+4)

domain

f (x) = - x^{2} - 3 x + 4

- 4 \leq x \leq 1

Interval Notation

[- 4, 1]

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 1

The function domain

- 4 \leq x \leq 1

f (x) = \frac{x - 1}{x ^{2} + 6 x - 27}

y = \frac{x + 1}{2 x + 1}

f (x) = ∣ x ∣ - x

\frac{x ^{2}}{6 - x}

f (x) = \frac{x - 2}{x ^{2} + 6 x - 16}

What is the domain of f(x)=sqrt(-x^2-3x+4) ?
The domain of f(x)=sqrt(-x^2-3x+4) is -4<= x<= 1