What is the domain of y=(x+1)/(2x+1) ?

The domain of y=(x+1)/(2x+1) is x -1/2

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domain of y=(x+1)/(2x+1)

domain

y = \frac{x + 1}{2 x + 1}

x < - \frac{1}{2} or x > - \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or x > - \frac{1}{2}

f (x) = ∣ x ∣ - x

\frac{x ^{2}}{6 - x}

f (x) = \frac{x - 2}{x ^{2} + 6 x - 16}

f (x) = - 4 + 3 x - 12

\frac{1}{2} x^{2} e^{x + 1}

What is the domain of y=(x+1)/(2x+1) ?
The domain of y=(x+1)/(2x+1) is x<-1/2 \lor x>-1/2