What is the domain of f(x)= 2/(\sqrt[3]{3x+2)} ?

The domain of f(x)= 2/(\sqrt[3]{3x+2)} is x -2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 2/(\sqrt[3]{3x+2)}

domain

x < - \frac{2}{3} or x > - \frac{2}{3}

Interval Notation

(- \infty, - \frac{2}{3}) \cup (- \frac{2}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{2}{3}

The function domain

x < - \frac{2}{3} or x > - \frac{2}{3}

f (x) = \frac{1}{\frac{1}{x} - 1}

f (x) = x y - y - 1 = 0

- x^{2} - 3 x + 10

y = \frac{2 x ^{3} - 3}{x ^{3} + 3 x ^{2} + 3 x + 1}

x - 16 + 16 - x

What is the domain of f(x)= 2/(\sqrt[3]{3x+2)} ?
The domain of f(x)= 2/(\sqrt[3]{3x+2)} is x<-2/3 \lor x>-2/3