What is the domain of y=(2x^3-3)/(x^3+3x^2+3x+1) ?

The domain of y=(2x^3-3)/(x^3+3x^2+3x+1) is x -1

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domain of y=(2x^3-3)/(x^3+3x^2+3x+1)

domain

y = \frac{2 x ^{3} - 3}{x ^{3} + 3 x ^{2} + 3 x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

x - 16 + 16 - x

y = \frac{1}{a ^{x}}

f (x) = - \frac{x - 2}{3} + 1

\frac{2 x}{5 x - 3}

f (x) = y^{2} = 16 - x^{2}

What is the domain of y=(2x^3-3)/(x^3+3x^2+3x+1) ?
The domain of y=(2x^3-3)/(x^3+3x^2+3x+1) is x<-1\lor x>-1