What is the domain of f(x)=sqrt(-(x-2)/3)+1 ?

The domain of f(x)=sqrt(-(x-2)/3)+1 is x<= 2

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domain of f(x)=sqrt(-(x-2)/3)+1

domain

f (x) = - \frac{x - 2}{3} + 1

x \leq 2

Interval Notation

(- \infty, 2]

Solution steps

Find non-negative values for radicals:

x \leq 2

The function domain

x \leq 2

\frac{2 x}{5 x - 3}

f (x) = y^{2} = 16 - x^{2}

f (x) = x \cdot ln (x^{2})

f (x) = 3 cot (2 x)

f (x) = \frac{8}{x + 1}

What is the domain of f(x)=sqrt(-(x-2)/3)+1 ?
The domain of f(x)=sqrt(-(x-2)/3)+1 is x<= 2