What is the domain of f(x)=(x-9)/(sqrt(x-2)) ?

The domain of f(x)=(x-9)/(sqrt(x-2)) is x>2

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domain of f(x)=(x-9)/(sqrt(x-2))

domain

f (x) = \frac{x - 9}{x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (t) = \frac{1}{t}

f (x) = \frac{2}{2 + 2 ^{\frac{1}{x}}}

f (x) = \frac{x - 2}{x ^{2} + 2 x - 8}

What is the domain of f(x)=(x-9)/(sqrt(x-2)) ?
The domain of f(x)=(x-9)/(sqrt(x-2)) is x>2