What is the domain of (x+4)/(\sqrt[3]{x+1)} ?

The domain of (x+4)/(\sqrt[3]{x+1)} is x -1

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domain of (x+4)/(\sqrt[3]{x+1)}

domain

\frac{x + 4}{3 x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = \frac{8}{x - 8}

\frac{2 x + 7}{3 9 - x}

f (t) = 6 t - \frac{2}{3 + 5 t}

lo g_{10} (x - 6)

y

What is the domain of (x+4)/(\sqrt[3]{x+1)} ?
The domain of (x+4)/(\sqrt[3]{x+1)} is x<-1\lor x>-1