What is the domain of y=(x+2)/(sqrt(x)) ?

The domain of y=(x+2)/(sqrt(x)) is x>0

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domain of y=(x+2)/(sqrt(x))

domain

y = \frac{x + 2}{x}

x > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x > 0

y = \frac{2 x ^{2}}{x ^{2} - 1}

\frac{x + 2}{2 x - 12}

f (x) = 5 x^{2} - 30 x + 49

f (x) = 2 x^{2} + x - 6

x^{5} - 3 x^{3} + 5 x

What is the domain of y=(x+2)/(sqrt(x)) ?
The domain of y=(x+2)/(sqrt(x)) is x>0