What is the domain of f(x)=arcsin((x-1)/(x+1)) ?

The domain of f(x)=arcsin((x-1)/(x+1)) is x>= 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=arcsin((x-1)/(x+1))

domain

f (x) = arcsin (\frac{x - 1}{x + 1})

x \geq 0

Interval Notation

Solution steps

Find known functions domain restrictions:

x \geq 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x \geq 0

f (x) = - (x - 4) (x + 2) (x - 1)

3 + x + 2

f (x) = 5 x - 2

\frac{x - 5}{x + 1}

h (x) = 8

What is the domain of f(x)=arcsin((x-1)/(x+1)) ?
The domain of f(x)=arcsin((x-1)/(x+1)) is x>= 0