What is the domain of (t^2+t-20)/(3t^2+11t-4) ?

The domain of (t^2+t-20)/(3t^2+11t-4) is t 1/3

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domain of (t^2+t-20)/(3t^2+11t-4)

domain

\frac{t ^{2} + t - 20}{3 t ^{2} + 11 t - 4}

t < - 4 or - 4 < t < \frac{1}{3} or t > \frac{1}{3}

Interval Notation

(- \infty, - 4) \cup (- 4, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

t = \frac{1}{3}, t = - 4

The function domain

t < - 4 or - 4 < t < \frac{1}{3} or t > \frac{1}{3}

f (θ) = cos (θ)

100 x

x + 14

f (x) = \frac{x + 1}{x ^{2} + 3 x - 40}

f (x) = 8750 \cdot 0.8 8^{0}

What is the domain of (t^2+t-20)/(3t^2+11t-4) ?
The domain of (t^2+t-20)/(3t^2+11t-4) is t<-4\lor-4<t< 1/3 \lor t> 1/3