What is the domain of f(x)=(x^4-1)/(x^2-1) ?

The domain of f(x)=(x^4-1)/(x^2-1) is x 1

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domain of f(x)=(x^4-1)/(x^2-1)

domain

f (x) = \frac{x ^{4} - 1}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = \frac{x - 1}{x ( x + 2 )}

\frac{5 x + 2}{7 x} 2 x

\frac{x - 7}{x ^{2} - 4 x - 12}

y = - 2 x^{3} - 12 x + 1

f (x) = \frac{x - 1}{x ^{2} + x - 6}

What is the domain of f(x)=(x^4-1)/(x^2-1) ?
The domain of f(x)=(x^4-1)/(x^2-1) is x<-1\lor-1<x<1\lor x>1