What is the domain of (x-7)/(x^2-4x-12) ?

The domain of (x-7)/(x^2-4x-12) is x 6

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domain of (x-7)/(x^2-4x-12)

domain

\frac{x - 7}{x ^{2} - 4 x - 12}

x < - 2 or - 2 < x < 6 or x > 6

Interval Notation

(- \infty, - 2) \cup (- 2, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 2

The function domain

x < - 2 or - 2 < x < 6 or x > 6

y = - 2 x^{3} - 12 x + 1

f (x) = \frac{x - 1}{x ^{2} + x - 6}

y = \frac{x + 2}{x ^{2} - 9}

b^{y}

\frac{2 ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )}

What is the domain of (x-7)/(x^2-4x-12) ?
The domain of (x-7)/(x^2-4x-12) is x<-2\lor-2<x<6\lor x>6