What is the domain of sqrt(x^2+4x) ?

The domain of sqrt(x^2+4x) is x = 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(x^2+4x)

domain

x^{2} + 4 x

x \leq - 4 or x \geq 0

Interval Notation

(- \infty, - 4] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 0

The function domain

x \leq - 4 or x \geq 0

h (x) = \frac{x ^{2} - 4}{2}

∣ 2 x ∣

f (x) = 7 x - 9

\frac{x - 3}{x - 5}

lo g_{10} (12 - x)

What is the domain of sqrt(x^2+4x) ?
The domain of sqrt(x^2+4x) is x<=-4\lor x>= 0