What is the domain of sqrt(4-\sqrt{x)} ?

The domain of sqrt(4-\sqrt{x)} is 0<= x<= 16

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domain of sqrt(4-\sqrt{x)}

domain

4 - x

0 \leq x \leq 16

Interval Notation

[0, 16]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 16

The function domain

0 \leq x \leq 16

f (t) = 5 t

f (t) = 3 t

x^{2} + 8 x - 20

y = 3 x^{2} - 4

f (x) = - 42 + 2 x

What is the domain of sqrt(4-\sqrt{x)} ?
The domain of sqrt(4-\sqrt{x)} is 0<= x<= 16