What is the domain of 5(sqrt(9-x^2)) ?

The domain of 5(sqrt(9-x^2)) is -3<= x<= 3

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domain of 5(sqrt(9-x^2))

domain

5 (9 - x^{2})

- 3 \leq x \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

The function domain

- 3 \leq x \leq 3

y = \frac{6 - t}{t ^{2} - t - 2}

f (x) = 3 - t

f (x) = \frac{1}{x}

f (x) = \frac{4 x - 1}{5}

E (x) = x^{2} - 4 + 9 - 3 x

What is the domain of 5(sqrt(9-x^2)) ?
The domain of 5(sqrt(9-x^2)) is -3<= x<= 3