What is the domain of f(x)= 1/(2x^2+x-6) ?

The domain of f(x)= 1/(2x^2+x-6) is x 3/2

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domain of f(x)= 1/(2x^2+x-6)

domain

f (x) = \frac{1}{2 x ^{2} + x - 6}

x < - 2 or - 2 < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - 2) \cup (- 2, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}, x = - 2

The function domain

x < - 2 or - 2 < x < \frac{3}{2} or x > \frac{3}{2}

f (x) = \frac{x + 5 - 1}{2}

f (x, y) = e^{y}

600 \cdot e^{x} + 2022

\frac{2 x + 9}{x - 1}

y = sin (x) + - cos (x)

What is the domain of f(x)= 1/(2x^2+x-6) ?
The domain of f(x)= 1/(2x^2+x-6) is x<-2\lor-2<x< 3/2 \lor x> 3/2