What is the domain of y=(|x|)/(sqrt(x^2-9)) ?

The domain of y=(|x|)/(sqrt(x^2-9)) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(|x|)/(sqrt(x^2-9))

domain

y = \frac{∣ x ∣}{x ^{2} - 9}

x < - 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

x < - 3 or x > 3

x x - 6 x

g (x) = 4 x^{2} - 3 x

f (x) = x^{2} - 4 + 3

\frac{x}{7}

f (x) = 3 x^{2} + x - 8

What is the domain of y=(|x|)/(sqrt(x^2-9)) ?
The domain of y=(|x|)/(sqrt(x^2-9)) is x<-3\lor x>3